A-level chemistry · Chapter 8
Redox & electrochemistry
Oxidation states, half-equations, electrode potentials
Oxidation is loss of electrons (oxidation state increases); reduction is gain. The oxidising agent is itself reduced.
Standard electrode potentials (298 K, 100 kPa, 1 mol dm⁻³)
- Measured against the standard hydrogen electrode, E° = 0.00 V by definition.
- Zn²⁺/Zn −0.76 V · Fe²⁺/Fe −0.44 V · H⁺/H₂ 0.00 V · Cu²⁺/Cu +0.34 V · Fe³⁺/Fe²⁺ +0.77 V · Ag⁺/Ag +0.80 V · Cl₂/Cl⁻ +1.36 V · MnO₄⁻/Mn²⁺ +1.51 V
- Cell EMF = E°(positive electrode) − E°(negative electrode). The more negative half-cell is oxidised (is the anode). Daniell cell check: 0.34 − (−0.76) = 1.10 V.
- A reaction is feasible if EMF > 0 — but feasible ≠ fast (kinetics can block it).
- AQA's data booklet contains no E° table — values are always supplied in the question, so learn the method, not the numbers.
Balancing half-equations in acid
- Balance the main atom, then O with H₂O, then H with H⁺, then charge with e⁻.
- Example: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O (purple → colourless: the classic self-indicating titration).
3.1.7Combining half-equations into full redox equations
Worked example — manganate(VII) titrating iron(II).
- Oxidation: Fe²⁺ → Fe³⁺ + e⁻ · Reduction: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
- Scale electrons equal: ×5 the iron half-equation.
- Add and cancel: 5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O
- Check: charge +17 both sides ✓
3.1.11.1Cells — conventional representation
- Written most-negative half on the left: Zn(s) | Zn²⁺(aq) || Cu²⁺(aq) | Cu(s). Single line = phase boundary, double line = salt bridge; EMF = E°(right) − E°(left).
- Salt bridge (KNO₃-soaked): completes the circuit by ion flow without mixing the solutions.
- Non-standard conditions shift E: increase [Cu²⁺] → its half-equation shifts right → E(cell) rises (Le Chatelier applied to electrodes).
3.1.11.2Commercial cells
- Non-rechargeable (e.g. zinc–carbon): reaction irreversible, EMF falls as reagents deplete.
- Rechargeable (lithium-ion): reactions reversed on charging by an applied potential.
- Hydrogen–oxygen fuel cell (alkaline): H₂ + 2OH⁻ → 2H₂O + 2e⁻ and O₂ + 2H₂O + 4e⁻ → 4OH⁻; overall 2H₂ + O₂ → 2H₂O. Constant EMF while fuel is supplied; water is the only product — but hydrogen is bulky to store and mostly made from fossil fuels.
Exam tip. "Feasible" from E° values means EMF > 0 for the direction written — but always add the kinetic caveat: a feasible reaction can be immeasurably slow (high activation energy).
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