A-level chemistry · Chapter 8

Redox & electrochemistry

Oxidation states, half-equations, electrode potentials

Oxidation is loss of electrons (oxidation state increases); reduction is gain. The oxidising agent is itself reduced.

Standard electrode potentials (298 K, 100 kPa, 1 mol dm⁻³)

Balancing half-equations in acid

  1. Balance the main atom, then O with H₂O, then H with H⁺, then charge with e⁻.
  2. Example: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O (purple → colourless: the classic self-indicating titration).

3.1.7Combining half-equations into full redox equations

Worked example — manganate(VII) titrating iron(II).
  1. Oxidation: Fe²⁺ → Fe³⁺ + e⁻  ·  Reduction: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
  2. Scale electrons equal: ×5 the iron half-equation.
  3. Add and cancel: 5Fe²⁺ + MnO₄⁻ + 8H⁺ → 5Fe³⁺ + Mn²⁺ + 4H₂O
  4. Check: charge +17 both sides ✓

3.1.11.1Cells — conventional representation

3.1.11.2Commercial cells

Exam tip. "Feasible" from E° values means EMF > 0 for the direction written — but always add the kinetic caveat: a feasible reaction can be immeasurably slow (high activation energy).
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