A-level chemistry · Chapter 1

Atomic structure

Subshells, ionisation energies, mass spectrometry

First ionisation energy — the energy required to remove one mole of electrons from one mole of gaseous atoms, forming one mole of gaseous 1+ ions. X(g) → X⁺(g) + e⁻

Trends across period 3

Electron configuration rules

Time-of-flight mass spectrometry

3.1.1.1Fundamental particles

ParticleRelative massRelative chargeWhere
Proton1+1nucleus
Neutron10nucleus
Electron1/1836−1shells / orbitals

3.1.1.3Successive ionisation energies — the evidence for shells

Worked example. An element's first four ionisation energies are 578, 1817, 2745, 11 578 kJ mol⁻¹.
  1. Jumps: ×3.1, ×1.5, then ×4.2 — the huge jump is after the 3rd electron.
  2. Three easily-removed outer electrons → group 3. (It is aluminium.)
Worked example — Ar from a mass spectrum. A sample of chlorine shows peaks at m/z 35 (abundance 75%) and 37 (25%).
  1. Ar = (35 × 75 + 37 × 25) ÷ 100 = 35.5
Exam tip. The ionisation energy definition needs all three markers: one mole of electrons, from gaseous atoms, forming gaseous 1+ ions. Missing "gaseous" loses the mark every time.

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Time-of-flight mass spectrometry, quantitatively

All four stages carry marks. Ionisation: either electron impact (a high-energy electron knocks one electron out: X(g) → X⁺(g) + e⁻ — used for low-mass samples, causes fragmentation) or electrospray (the sample gains a proton from the solvent: X(g) + H⁺ → XH⁺(g) — used for large biological molecules; remember the detected mass is M+1). Acceleration: an electric field gives every ion the same kinetic energy, so lighter ions end up faster. Flight: ions drift through a field-free tube; since KE = ½mv², the speed is v = √(2KE/m) and the flight time over distance d is t = d√(m/2KE) — time is proportional to √m. Detection: each ion gains an electron at the detector; the tiny current is proportional to abundance.

Worked example. A ²⁴Mg⁺ ion (m = 3.98 × 10⁻²⁶ kg) is accelerated to KE = 4.52 × 10⁻¹⁶ J. v = √(2 × 4.52 × 10⁻¹⁶ ÷ 3.98 × 10⁻²⁶) = 1.51 × 10⁵ m s⁻¹. Over a 0.800 m tube, t = 0.800 ÷ 1.51 × 10⁵ = 5.3 × 10⁻⁶ s. A ²⁶Mg⁺ ion arrives √(26/24) = 1.041 times later.

Reading mass spectra

Successive ionisation energies — the evidence for shells

Removing electrons one by one from the same atom gives a rising staircase with giant jumps between shells. For sodium: the 1st IE is small (lone 3s electron), then a huge jump to the 2nd (now breaking into the full n = 2 shell), then eight steadily rising values, then another leap into n = 1. Count the electrons removed before each jump to read off the group: an element whose big jump comes after the 2nd ionisation energy is in Group 2.

The two classic first-IE anomalies

Configurations of ions

Write the atom first, then remove from the highest n first — 4s before 3d for transition metals: Fe is [Ar]3d⁶4s², Fe²⁺ is [Ar]3d⁶, Fe³⁺ is [Ar]3d⁵ (extra stability of the half-filled d-subshell explains why Fe²⁺ oxidises easily). Negative ions add electrons to the next empty orbital: O²⁻ is 1s²2s²2p⁶, isoelectronic with Ne, F⁻, Na⁺ and Mg²⁺ — but their radii differ because the nuclear charge differs.

Definitions bank (mark-scheme wording). Relative atomic mass: the mean mass of an atom of an element ÷ 1/12 the mass of an atom of ¹²C. Relative isotopic mass: the mass of a single isotope on the same scale. First ionisation energy: the energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions — X(g) → X⁺(g) + e⁻. State symbols are compulsory.

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The evolving model of the atom (spec 3.1.1.1)

Dalton: indivisible spheres. Thomson (1897): discovery of the electron → "plum pudding" of negative electrons in positive dough. Rutherford (1911): alpha-particle scattering — most passed straight through gold foil, a tiny fraction bounced back → mass and positive charge concentrated in a minute nucleus. Bohr: electrons in fixed energy levels, explaining line spectra. Modern quantum model: orbitals as probability regions. The examinable lesson: models are accepted, tested and replaced as evidence accumulates — name the evidence when you name the model.

Orbitals, subshells and the three filling rules

First ionisation energies across Period 3 — the data

ElementNaMgAlSiPSClAr
IE₁ / kJ mol⁻¹4967385787861012100012511521

General rise (increasing nuclear charge, same shell, similar shielding) with the two dips: Al (3p above 3s) and S (first 3p pairing). Sketch questions want the zigzag shape with those two elements below the trend line, labelled with the reasons.

Mass spectrometry: the corner cases

Reverse-abundance calculation. Gallium (Aᵣ = 69.7) has isotopes 69 and 71. Let x% be ⁶⁹Ga: 69x + 71(100−x) = 6970 → 7100 − 2x = 6970 → x = 65. So 65% ⁶⁹Ga, 35% ⁷¹Ga. This inversion appears constantly in exams.

Applications you can quote

Exam pattern. "Explain why the first ionisation energy of X is greater/less than Y" is answered with exactly three factors: nuclear charge, shielding, and distance/subshell of the outer electron. Pick the two that differ, state the third is similar, conclude. Never mention "wanting" a full shell — atoms want nothing.
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